Would like to know what is the voltage range the PCM sends to this alternator.
This is off a 2000 Durango. I have tried a standard electronic voltage
regulator but it sends 12 volts to this alternator and was told that they
require less voltage to work properly (5v?). Would appreciate any help with
this project.
Thanks, evlu
Big Al - 27 Aug 2007 00:30 GMT
> Would like to know what is the voltage range the PCM sends to this alternator.
> This is off a 2000 Durango. I have tried a standard electronic voltage
> regulator but it sends 12 volts to this alternator and was told that they
> require less voltage to work properly (5v?). Would appreciate any help with
> this project.
> Thanks, evlu
The way it works is like this. The PCM or regulator sends voltage (actually
current) to the field one of two ways, by varying the + voltage to the
field, or by always sending battery voltage and varying the ground circuit.
Either way, it send more and more current until the battery reaches the
desired voltage, then it backs off. There is no set voltage. The required
voltage to the field will vary depending on the load, I.E. headlamps off or
on. AC off or on. And so on.
Al
Bryan - 27 Aug 2007 02:03 GMT
> Would like to know what is the voltage range the PCM sends to this alternator.
> This is off a 2000 Durango. I have tried a standard electronic voltage
> regulator but it sends 12 volts to this alternator and was told that they
> require less voltage to work properly (5v?). Would appreciate any help with
> this project.
> Thanks, evlu
The alternator field winding is driven by a PWM (Pulse Width Modulated)
signal that goes from zero to 12V. The more output current needed from the
alternator, the longer the ON time and the less OFF time of the PWM signal,
affecting the average voltage to (and current in) the field winding.
Examples:
12V x 10% ON time = 1.2V
12V x 50% ON time = 6.0V
12V x 90% ON time = 10.8V
Thus, the duty-cycle for 5V would be approximately (5 / 12) x 100 = 41.67%.
The current in the field winding is directly related to the average voltage
to it. However, since Power = Volts x Amperes, the power consumed in the
field isn't a straight line.
Bryan