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Car Forum / Volkswagen / Air Cooled Volkswagen Cars / May 2007

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transistorizing vw ignition

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klashniv - 22 May 2007 13:23 GMT
I would like to add a transistor to my vw's ignition system to do the
switching of the current to the coil. I have got two different
possible circuits online

http://picasaweb.google.com/klashniv/Transistors (the first 2 pics)

I have lots of NPN transistors from various power units, so would like
to use NPN while keeping the points to do the triggering.

Came up with the 3rd circuit in the link above. I will add a resistor
to limit current flowing through the points and a diode to prevent
current induced in coil's primaries from messing up the transistor.

Anybody done something like this before? Any reason circuit 3 wouldn't
work?

Start circuit building this weekend.
Bill Spiliotopoulos - 22 May 2007 14:24 GMT
Some theory of how the ignition system works.

To get a spark, you need first to "charge" the coil with the highest current
it can handle. Charging coil with current takes some time, like charging a
capacitor with voltage.  When the max amount of current flows through the
coil, you have a strong magnetic field in the coil's windings.  When you
break the primary circuit suddenly, the magnetic field colapses, and this
change in magnetic field tries to induct current in both primary and
secondary windings.
But because both windings are open (secondary has a gap on the spark plugs /
distributor rotor,  and the primary on the points or transistor switch), the
voltage will automaticaly rise until it can "jump" and close the circuit
(spark occurs in either primary or seconday circuit) to discharge the coil.
The voltage to the secodary will be couple of hunderd times higher
(depending on thr ratio of the windings), so it will easier create a spark
and discharge the coil.

If you create a path for the "discharging" current in the primary with a
diode, the coil will discharge easily without creating the necessary spike
to provide the spark on the secondary.  So forget transistor protection with
a diode.

The only thing that will limit the spike (and the spark voltage) is the
capacitor in the primary, so a small enough capacitor must be used.
Electronic points do not really need a capacitor. Points need it to limit
the spike so that less sparking occurs on the points and so that less of the
coil's energy is lost from sparking on the points (and the points will live
longer with less sparking).

You will thus need a transistor with a high Vce voltage, around 300-400V. It
would probably work with a Vce > 150V but you need a safety margin so that
you can use a larger gap on the plugs, or remove the capacitor completely to
get a stronger spark.

Circuit 3 would be much better, if the hot side of the points was connected
directly to +12V, and not to the coils output. As you said a resistance is
needed to limit transistor's base current and a ballast resistor is needed
to limit coil current (if not already included in the coil).

Bill Spiliotopoulos,
'67 bug.
klashniv - 23 May 2007 05:40 GMT
> Some theory of how the ignition system works.
>
[quoted text clipped - 37 lines]
> Bill Spiliotopoulos,
> '67 bug.

Bill,

Thanks for taking the time to look at the circuits and give your
valuable input. I apologize for the double post, I got an error the
first time and thought the message hadn't been transmitted.

The diode I had in mind would have been placed to prevent current
flowing any other way, other than the right way through the
transistor.

Is there any other way of protecting the transistor, other than
limiting base current.?
Bill Spiliotopoulos - 23 May 2007 12:46 GMT
An NPN / PNP transistor may be damaged (if correctly connected) in the
following ways.
1) Over current through CE.
2) Over current through BE.
3) Over voltage to CE.
4) Over voltage to BE.
5) Over-temperature, or exceeding the power capabilities of the transistor
and not using correct cooling.

- Case 1 is covered by the ballast resistor (resistor in series with the
coil, some times incorporated inside the coil) and by using a transistor
capable of the current.
- Case 2 is covered by a resistor driving the base of the transistor. You
have to calculate the value of this resistor, because the current capability
through CE, is the base current multiplied by the b constant (current
amplification constant) of the transistor.
- Case 3 is covered by using a transistor with capability of withstanding
high Vce, and by conditioning the shape of the spike with a capacitor
between C,E.
- Case 4 is covered by feeding the points directly from 12V and not from the
coil output.
- Case 5 is covered by selecting a transistor with the appropriate wattage,
and using a big cooler for it.

Note that usually common NPN transistors you may have in your box from power
supply applications or power amplifiers, do not have a high enough Vce
voltage.  You should go shopping for such a transistor, or maybe find an old
TV and see if what they are using for driving the primary of the High
Voltage Transformer suits your needs.

This is the schematic I am referring to (use a constant width font to
display properly).

  +12V -------+---------------------------------+
              |                                 |
              |                                 |
            [ C ]                               |
            [ O ]                               |
            [ I ]                               |
            [ L ]                               |
            [   ]                               |
            [ P ]                               |
            [ R ]                               |
            [ I ]                               |
            [ M ]                               |
            [ A ]                               o |
            [ R ]                                 |
            [ Y ]                                 |-  Points or electronic
switch.
              |                                   |
              |                                 o |
              |                                 |
              \                                 |
              /                                 |
              \                                 |
              / Rl (Ballast resistor)            |
              \                                 |
              /                                 |
              \                                 |
              /                                 |
              |                                 |
        +-----+                                 |
        |     |                                 |
        |     |C                                |
        |     \                                 |
  Cf  =====    \|B          Rb (Base resistor)  |
      =====     |-------/\/\/\/\/\--------------+
        |      /|
        |     /   NPN
        |     |E
        +-----+
              |
              |
            _____
            /////
           Ground

Bill Spiliotopoulos,
'67 bug.

>> Some theory of how the ignition system works.
>>
[quoted text clipped - 66 lines]
> Is there any other way of protecting the transistor, other than
> limiting base current.?
klashniv - 28 May 2007 07:55 GMT
>From all the research I have done, the replies and emails I have
received from various members of this group (thank you to all who
wrote) and my own testing in the laboratory, I can safely say circuit
3 will work BUT it wouldn't last long. A bit of protection has to be
added to safeguard the transistor from effects of the coil's
inductance, heat, too much current and voltage.

Anyways, I will believe this thread will point people searching for
similar information in the right direction.
 
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